AN645
MAINS RECTIFICATION FOR THE GS100T300-x
Application NOTE
The Gs100t300-x Is A Family Of Dc-dc Converters With Different Output Voltages (x), That Can Deliver
An Output Power Of 100 Watt When An Unregulated Dc Voltage Source Of 300 V Typical Is Available. The
key data for GS100T300-x are:
Po = Output Power = 100 Watt Vo = Output Voltage = From 3.3 To 48 Vdc = Efficiency = 80 % Min.
Vin = Input voltage = 200 to 400 VDC IinRMS = Input RMS current = 0.88 ARMS
The Following Note Describes How To Obtain An Unregulated Dc Input Voltage From The Mains. Four
Examples Are Considered: The Europe And Usa Mains, And, For Each Of Them, With And Without The
hold-on characteristic.
The Hold-on Characteristic Is The Ability Of The Input Voltage Source To Mantain A Dc Voltage Higher
Than The Minimum Input Voltage Of The Dc-dc Converter, Even In Case Of A Mains Interruption Of 1
cycle.
1. European mains without the hold on characteristic.
The European mains characteristics are:
Vinac = 230 VRMS 15 % 240 VRMS 10 %
f = 50 Hz
The Minimum Ac Voltage Is, Therefore, 195 Vrms While The Maximum Ac Voltage Is 264 Vrms. A Bridge
Rectifier As Shown In Fig. 1 Can Be Used To Obtain The Required Unregulated Dc Voltage.
Figure 1: AC-DC converter for Europe Mains.
AC mains
AN645/0594
C Unregulated DC voltage
MAINS RECTIFICATION AND FILTERING
The typical waweform for this type of rectifier is shown in fig. 2 where:
Vc = Voltage Across Capacitor C. Vpk = Peak Value Of The Input Ac Voltage. Vmin = Minimum Voltage
Across Capacitor C. Tch = Charging Time Of The Capacitor C Tdch = Discharging Time Of The Capacitor
C Ich = Peak Charge Current For The Capacitor C Idc = Average Input Current T = Total Time For One
complete cycle
The Total Energy Win To Be Supplied By The Capacitor C During One Full Cycle Of The Mains Is:
Where Pin Is The Input Power In Watt Of The Gs100t300-x And F Is The Mains Frequency In Hz. In This
case:
100 0.8
During Each Half Cycle, The Capacitor Has To Deliver 1/2 Win And Its Voltage Will Drop From Vpk To
Vmin. The following equation applies:
C (V 2
therefore
Win V2
In this case:
Vpk = 2
VinRMSmin 4 = 1.41
195 4 = 271 V
Where 4 V Is A Good Assumption For The Voltage Drop Across The Rectifying Diodes And The Input
Filter. According To The Gs100t300-x Data, Vmin=200 V. Therefore, From Equation (3):
2.5 2712 2002